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9x^2-90x+1=0
a = 9; b = -90; c = +1;
Δ = b2-4ac
Δ = -902-4·9·1
Δ = 8064
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8064}=\sqrt{576*14}=\sqrt{576}*\sqrt{14}=24\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-24\sqrt{14}}{2*9}=\frac{90-24\sqrt{14}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+24\sqrt{14}}{2*9}=\frac{90+24\sqrt{14}}{18} $
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